30v^2-29v-1=0

Solution for 30v^2-29v-1=0 equation:

30v^2-29v-1=0

a = 30; b = -29; c = -1;
Δ = b2-4ac
Δ = -292-4·30·(-1)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-31}{2*30}=\frac{-2}{60}
=-1/30
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+31}{2*30}=\frac{60}{60}
=1
$